1288D - Minimax Problem - CodeForces Solution


binary search bitmasks dp *2000

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C++ Code:

#include<bits/stdc++.h>
using namespace std;
#define ll long long
#define pb push_back
#define pf push_front
#define pof pop_front
#define pob pop_back
#define pell pair<ll,ll>
#define pei pair<int,int>
#define dpe pair<ll,pe>
#define x first
#define y second
const ll maxn=3e5+10,maxmask=(1<<8);
int n,m,a[maxn][10],vt[maxmask];
pei ans;
bool check(int x)
{
    for(int i=0;i<(1<<n);i++)
        vt[i]=0;
    for(int i=1;i<=m;i++)
    {
        int tmp=0;
        for(int j=1;j<=n;j++)
        {
            if(a[i][j]>=x)
            {
                tmp+=(1<<(j-1));
            }
        }
        vt[tmp]=i;
    }
    for(int i=0;i<(1<<n);i++)
    {
        for(int j=0;j<(1<<n);j++)
        {
            if((vt[i]&&vt[j])&&((i|j)==(1<<n)-1))
            {
                ans={vt[i],vt[j]};
                return 1;
            }
        }
    }
    return 0;
}
int main()
{
    ios_base::sync_with_stdio(false);
    cin.tie(NULL);
    cout.tie(NULL);
    if(fopen("111.INP","r"))
    {
        freopen("111.INP","r",stdin);
        freopen("111.OUT","w",stdout);
    }
    cin>>m>>n;
    for(int i=1;i<=m;i++)
    {
        for(int j=1;j<=n;j++)
        {
            cin>>a[i][j];
        }
    }
    int l=0,r=1e9;
    while(l<=r)
    {
        int mid=(l+r)/2;
        if(check(mid)) l=mid+1;
        else r=mid-1;
    }
    cout<<ans.x<<" "<<ans.y;
}

	 	  		 	 	  	   				 			     	


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